[reportlab-users] Force Table to dispaly in one page rather than in next page

[Asif Jamadar]

Hey andy,

	I have another question about tables in reportlab. Currently in my app my table is dynamic, means it uses data from the database. Now my question is if values in database are increased then how should I fit table in one page.

I tested using multiple values from the database so table is continued in next page so how should I force this table to be appeared in a single page?



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Message: 1
Date: Thu, 23 Jun 2011 05:14:03 +0000
From: Asif Jamadar <asif.jamadar at rezayat.net>
Subject: [reportlab-users] Saving the generated report into Django
	model
To: "reportlab-users at lists2.reportlab.com"
	<reportlab-users at lists2.reportlab.com>
Message-ID:
	<CC0CC2862BF94D41A65DC4511A12B49328FCF73C at weaver.REZAYAT.NET>
Content-Type: text/plain; charset="us-ascii"

I found the solution,

	def report(request)

	  response = HttpResponse(mimetype='application/pdf')
    	  response['Content-Disposition'] = 'attachment;filename=ANALYSIS_REPORT.pdf'
	  buffer = StringIO()

    	  doc = SimpleDocTemplate(buffer)
		
		#Create the PDF
	

	 doc.build(document, onLaterPages=header_footer)
    
    	 pdf = buffer.getvalue()
    
    	 myfile = ContentFile(pdf)
	
	 m = Report()
    
       m.file.save('test.pdf', myfile)
	
	 response.write(pdf) 

    	 return response

Here Report is the model and file is the field of Report model.

Hope it will help someone 



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Today's Topics:

   1. how can i save PDF report into django model (Asif Jamadar)
   2. Re: how can i save PDF report into django model (Andy Robinson)


----------------------------------------------------------------------

Message: 1
Date: Wed, 22 Jun 2011 05:23:48 +0000
From: Asif Jamadar <asif.jamadar at rezayat.net>
Subject: [reportlab-users] how can i save PDF report into django model
To: "reportlab-users at lists2.reportlab.com"
	<reportlab-users at lists2.reportlab.com>
Message-ID:
	<CC0CC2862BF94D41A65DC4511A12B49328FCE637 at weaver.REZAYAT.NET>
Content-Type: text/plain; charset="us-ascii"

How can I save the dynamically generated PDF report into separate django model (database) as file.

I created model called 'Reports', in this model I defined a FileField.

In models.py

Class Report(models.Model):

file  = models.FileField(upload_to='uploads/documents)'


In views.py

                def  report(request):

         response = HttpResponse(mimetype='application/pdf')
                         response['Content-Disposition'] = 'attachment;filename=ANALYSIS_REPORT.pdf'
                        buffer = StringIO()
                       doc = SimpleDocTemplate(response)
                       ...................................................................
                      ....................................................................
                     doc.build(document)
                     pdf = buffer.getvalue()

                   myfile = ContentFile(pdf)
                   m = Report()
                  m.file.save('test.pdf', myfile)
                  return response

But the above code saves the EMPTY report.  So any advice on how to save the generated PDF report in django model

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Message: 2
Date: Wed, 22 Jun 2011 08:50:06 +0100
From: Andy Robinson <andy at reportlab.com>
Subject: Re: [reportlab-users] how can i save PDF report into django
	model
To: reportlab-users <reportlab-users at lists2.reportlab.com>
Message-ID: <BANLkTimTnS13n41mJaDGofSgQ5=mVKbx_w at mail.gmail.com>
Content-Type: text/plain; charset=UTF-8

On 22 June 2011 06:23, Asif Jamadar <asif.jamadar at rezayat.net> wrote:

> ???????? response = HttpResponse(mimetype='application/pdf')

>

> ?? ???????????? ?????????response['Content-Disposition'] =

> 'attachment;filename=ANALYSIS_REPORT.pdf'

>

> ??????????????? ??????? buffer = StringIO()

> ??????????????? ?????? doc = SimpleDocTemplate(response)

> ??????????????? ???? doc.build(document)

> ??????????????? ???? pdf = buffer.getvalue()


It looks from this like you are not actually using the 'buffer' variable.  Try
    doc.build(document, filename=buffer)

Originally we allowed a filename, but later we generalised it to allow
a file-like object.

- Andy

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------------------------------

Message: 2
Date: Thu, 23 Jun 2011 08:17:58 +0100
From: Andy Robinson <andy at reportlab.com>
Subject: Re: [reportlab-users] Saving the generated report into Django
	model
To: reportlab-users <reportlab-users at lists2.reportlab.com>
Message-ID: <BANLkTinAWGQGdfQWrVAKfexb1Q16fpB6UQ at mail.gmail.com>
Content-Type: text/plain; charset=UTF-8

On 23 June 2011 06:14, Asif Jamadar <asif.jamadar at rezayat.net> wrote:

> I found the solution,

> ? ? ? ? ?doc = SimpleDocTemplate(buffer)

Apologies, my memory was failing me (I usually do this through RML) -
this is the right way to do it.

- Andy


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