[reportlab-users] Unconditionally split a string at the end of a cell.

[Martin Weissenboeck]

I have found the answer:

styleN.wordWrap = 'CJK'


It took a lot of hours to find this information in a newsgroup. It would be
nice to have this information in the documenation.


2012/1/6 Martin Weissenboeck <mweissen at gmail.com>


> Hi,

>

> I have a paragraph like

>

> p = Paragraph('ABCDEFG',styleN)

>

>

> The string does not contain any spaces.

> This paragraph becomes part of a table. Width of the column is (e.g.) 5*mm.

> I expected the text to be broken in some lines. But there is always one

> line.

>

> I have tried to use the function simpleSplit

>

> p5 = simpleSplit('1ABCDEFG', 'ArialNarrow', 9.0, 5*mm)

>

>

> but without spaces the result is again only one string.

>

> Paragraph(...).breakLinesCJK(5*mm) splits the line, but it seems to be

> complicated to put the parts into the table.

>

> I think there should be a simple way to unconditionally split a string at

> the end of a cell.

> Any ideas?

>

> Martin

>

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